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select下拉列表菜单中超链接跳转的实现代码
- <script LANGUAGE="javascript">
- <!--
- function load(form) {
- var url = form.list.options[form.list.selectedIndex].value;
- if (url != "") open(url, "_self");
- return false;
- }
- // -->
- </script>
- <form NAME="menu" onSubmit="return load(this)">
- <p><select id="select2" name="list" onChange="load(this.form)" size="1" class="90V" style="background-color: rgb(196,226,103)">
- <option selected >---下拉列表超链接演示---</option>
- <option value="http://www.panpan.org/">盼盼资源网</option>
- <option value="http://www.panpan.org/">盼盼资源网</option>
- <option value="http://www.panpan.org/">盼盼资源网</option>
- <option value="http://www.panpan.org/">盼盼资源网</option>
- </select></p>
- </form>
复制代码
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